5t^2-10t+25=O

Solution for 5t^2-10t+25=O equation:

5t^2-10t+25=

We move all terms to the left:

5t^2-10t+25-()=0

We add all the numbers together, and all the variables

5t^2-10t=0

a = 5; b = -10; c = 0;
Δ = b2-4ac
Δ = -102-4·5·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-10}{2*5}=\frac{0}{10}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+10}{2*5}=\frac{20}{10}
=2
$